Quote: Originally Posted by Zen00
Since you all are enjoying math then how about this one?
A bucket has a hole in it. The water flows out of that hole at a rate of 2 gallons per minute. How big is the hole?
US gals or Imperial gals ??
2 gals / min US = 3.78533 Liters/Minute * 2. (gas fitting stats).
Calculate cylindrical vol from a minutes flow and you should get the hole size.
(Vol = π*r**2*h) you can do the maths.
While you have 2 variables r (radius) and h height only ONE set of values will fit the equation.
For US measurements the hole size should be around 1/2 inch - any old gas fitter / Engineer will tell you that this size pipe will sustain a flow of around 2.2 US gals / min -- near enough the right answer. So consider your hole as the "pipe outlet".
(I'm cheating here - I sometimes to some gas work for neighbours -- I.T doesn't pay anything like it used to anymore and I can get more money spending Sunday repairing a "Bog" or a gas boiler than 3 days of stupid management screaming in an I.T office).