Windows 7: Drive Letters, EasyBCD

Hi, all
Actually my computer is equipped with a 300GB drive as boot-device with two equal sized partitions on it to alternatively boot either Vista x64 (default at the moment) and Windows 7 x64 alternatively.
It depends on which OS I boot, how both partitions get drive letters assigned:
If I boot into Vista, the Vista partition gets drive letter C:, and the Windows 7 partition gets drive D:
If I boot into Windows 7, that partition gets drive letter C: and Vista will become the D: (Just switching)
But now I start to use EasyBCD 2.0, the Beta version, in Windows 7: After updating from Windows 7 Build 7100 to 7229 it shows me booting Vista from drive D: and Windows 7 from drive C:
Before I did the update, the regular EasyBCD 1.72 shows when Vista is booted, to boot Vista from drive C: and Windows 7 from drive D:
Is there anywhere out there a simple description on how the drive letters of startable devices are allocated?
What about drive letters in BCD?

Thanks in advance,

Oblomow

Well, this is a common 'feature' in Windows... Whichever Windows you use, it will assign itself as C: and not D:. This 'feature' is still in Windows because some apps WILL FORCE themselves to install in C:. Imagine if the OS you have booted is D: and when you boot it, it sees itself in D:, when you want to install a HARD-coded app(well written apps won't do this), it will install in C: (Which is your Vista drive even though you running 7) this will screw up everything, so i recommend you to leave things as they are.

1 way to avoid this 'feature' from working is to insert 7 disc in Vista and install 7 (Use custom option)>install it in the D: drive> This way when done installing, you will see 7 in D:

BTW, EASY BCD 2.0 IS IN BETA(as you said)... I wouldn't use it on my machines.... I would use the latest 'Stable' version. and i can't explain about the way Easy BCD works coz i now only have a single partition 80 GB drive.... 500 GB went RMA..
PS: I've used Easy BCD b4....