Actually my computer is equipped with a 300GB drive as boot-device with two equal sized partitions on it to alternatively boot either Vista x64 (default at the moment) and Windows 7 x64 alternatively.
It depends on which OS I boot, how both partitions get drive letters assigned:
If I boot into Vista, the Vista partition gets drive letter C:, and the Windows 7 partition gets drive D:
If I boot into Windows 7, that partition gets drive letter C: and Vista will become the D: (Just switching)
But now I start to use EasyBCD 2.0, the Beta version, in Windows 7: After updating from Windows 7 Build 7100 to 7229 it shows me booting Vista from drive D: and Windows 7 from drive C:
Before I did the update, the regular EasyBCD 1.72 shows when Vista is booted, to boot Vista from drive C: and Windows 7 from drive D:
Is there anywhere out there a simple description on how the drive letters of startable devices are allocated?
What about drive letters in BCD?
Thanks in advance,