New
#11
11111111.11111111.11111111.11000000<<<<<<leaves you 64 ip address on this subnet
192.168.1.2 - 192.168.1.62 would be your usable addresses with a 255.255.255.192 subnet mask. Assuming you use your first usable 192.168.1.1 for the ip address on it's LAN side.
Also with a 255.255.255.192 subnet mask on the 42.x.x.x subnet you will only have 42.242.120.193 - 42.242.120.254 as usable hosts.