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Windows 7: Anybody good at algebra?

04 Oct 2010   #31
arkhi

Windows 2000 5.0 Build 2195
 
 

I miss math so much I feel like doing your homework LOL. Let me think about it. Hmmm..

EDIT: So I wanted to use MS Math so I can template equations so it's easier to understand and that solve it a bit, but that thing freaking did it for me. So here it is. I'm going to leave the last 2 steps out since I don't want to spoon feed. The last number is up to you okay?


Attached Images
Anybody good at algebra?-math1.png Anybody good at algebra?-math2.png Anybody good at algebra?-math3.png 
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05 Oct 2010   #32
Boomstick777

Windows 7 x64 Enterprise
 
 

Is this the correct answer for question 'b'

b = k/a + 2

I used this method
a = sqr(b)/k + 2
a x
sqr(b) = sqr(b)/k + 2 xsqr(b)
a x b = k + 2
a x b/a = k/a +2


Answer - b = k/a +2
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05 Oct 2010   #33
Kirsch

Windows 7 Ultimate
 
 

When did they add letters
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.

05 Oct 2010   #34
Francis93

Windows 7 Ultimate x64
 
 

Nah. I suck at Algebra.
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05 Oct 2010   #35
Dwarf

Windows 8.1 Pro RTM x64
 
 

Let's go through this step by step.

a = sqr (b) / k + 2

sqr (b) / k = a - 2

sqr (b) = k (a -2)

sqr (b) = ka - 2k

b = (ka - 2k) x (ka - 2k)

b = kČaČ - 4kČa + 4kČ (answer)

Check using a = 6 and k = 3

b = (3Č x 6Č) - (4 x 3Č x 6) + (4 x 3Č)

b = 324 - 216 + 36

b = 144

Substituting b = 144 into the first equation, a = sqr (b) / k + 2, we get

a = (sqr (144) / 3) + 2

a = (12 / 3) + 2

a = 4 + 2

a = 6

So the answer is

b = kČaČ - 4kČa + 4kČ

Not bad, considering that it is about 30yrs since I did any Algebra. Hopefully, this should help you with the rest of the questions if you approach them in a similar way. Don't forget to do the checking, substituting actual numbers, as shown above. You will need to work out for yourself suitable numbers to use at this step.
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05 Oct 2010   #36
Kirsch

Windows 7 Ultimate
 
 

Nice Job Dwarf!!
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05 Oct 2010   #37
mickey megabyte

ultimate 64 sp1
 
 

anybody good at washing up?

i've got a nice pile of dirty dishes growing in my kitchen..
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05 Oct 2010   #38
Dwarf

Windows 8.1 Pro RTM x64
 
 

Quote   Quote: Originally Posted by Kirsch View Post
Nice Job Dwarf!!
Thanks.
Quote   Quote: Originally Posted by mickey megabyte View Post
anybody good at washing up?

i've got a nice pile of dirty dishes growing in my kitchen..
I think I'll give that one a miss.
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05 Oct 2010   #39
The Howling Wolves

Windows 7 Home Premium 64bit
 
 

Quote   Quote: Originally Posted by Dwarf View Post
Let's go through this step by step.

a = sqr (b) / k + 2

sqr (b) / k = a - 2

sqr (b) = k (a -2)

sqr (b) = ka - 2k

b = (ka - 2k) x (ka - 2k)

b = kČaČ - 4kČa + 4kČ (answer)

Check using a = 6 and k = 3

b = (3Č x 6Č) - (4 x 3Č x 6) + (4 x 3Č)

b = 324 - 216 + 36

b = 144

Substituting b = 144 into the first equation, a = sqr (b) / k + 2, we get

a = (sqr (144) / 3) + 2

a = (12 / 3) + 2

a = 4 + 2

a = 6

So the answer is

b = kČaČ - 4kČa + 4kČ

Not bad, considering that it is about 30yrs since I did any Algebra. Hopefully, this should help you with the rest of the questions if you approach them in a similar way. Don't forget to do the checking, substituting actual numbers, as shown above. You will need to work out for yourself suitable numbers to use at this step.
Dwarf,
Nice job going step by step in solving his problem.
Could have done that early on in the post but thought it was important for the OP to practice and learn on his own. Isn't that the way we learned how to algebra?
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05 Oct 2010   #40
Dwarf

Windows 8.1 Pro RTM x64
 
 

I'm leaving the rest for him to work out on his own. Besides, the image isn't very clear with the other equations.
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