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# Windows 7: Anybody good at algebra?

 04 Oct 2010 #31 arkhi Windows 2000 5.0 Build 2195 782 posts I miss math so much I feel like doing your homework LOL. Let me think about it. Hmmm.. EDIT: So I wanted to use MS Math so I can template equations so it's easier to understand and that solve it a bit, but that thing freaking did it for me. So here it is. I'm going to leave the last 2 steps out since I don't want to spoon feed. The last number is up to you okay? Attached Images My System Specs
 05 Oct 2010 #32 Boomstick777 Windows 7 x64 Enterprise 94 posts Is this the correct answer for question 'b' b = k/a + 2 I used this method a = sqr(b)/k + 2 a x sqr(b) = sqr(b)/k + 2 xsqr(b) a x b = k + 2 a x b/a = k/a +2 Answer - b = k/a +2 My System Specs
 05 Oct 2010 #33 Kirsch Windows 7 Ultimate 1,224 posts La Crosse, WI When did they add letters My System Specs
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 05 Oct 2010 #34 Francis93 Windows 7 Ultimate x64 2,176 posts Nah. I suck at Algebra. My System Specs
 05 Oct 2010 #35 Dwarf Windows 8.1 Pro RTM x64 10,375 posts Doncaster, UK Let's go through this step by step. a = sqr (b) / k + 2 sqr (b) / k = a - 2 sqr (b) = k (a -2) sqr (b) = ka - 2k b = (ka - 2k) x (ka - 2k) b = kČaČ - 4kČa + 4kČ (answer) Check using a = 6 and k = 3 b = (3Č x 6Č) - (4 x 3Č x 6) + (4 x 3Č) b = 324 - 216 + 36 b = 144 Substituting b = 144 into the first equation, a = sqr (b) / k + 2, we get a = (sqr (144) / 3) + 2 a = (12 / 3) + 2 a = 4 + 2 a = 6 So the answer is b = kČaČ - 4kČa + 4kČ Not bad, considering that it is about 30yrs since I did any Algebra. Hopefully, this should help you with the rest of the questions if you approach them in a similar way. Don't forget to do the checking, substituting actual numbers, as shown above. You will need to work out for yourself suitable numbers to use at this step. My System Specs
 05 Oct 2010 #36 Kirsch Windows 7 Ultimate 1,224 posts La Crosse, WI Nice Job Dwarf!! My System Specs
 05 Oct 2010 #37 mickey megabyte ultimate 64 sp1 8,601 posts anybody good at washing up? i've got a nice pile of dirty dishes growing in my kitchen.. My System Specs
 05 Oct 2010 #38 Dwarf Windows 8.1 Pro RTM x64 10,375 posts Doncaster, UK Quote: Originally Posted by Kirsch Nice Job Dwarf!! Thanks.    Quote: Originally Posted by mickey megabyte anybody good at washing up? i've got a nice pile of dirty dishes growing in my kitchen.. I think I'll give that one a miss. My System Specs
 05 Oct 2010 #39 The Howling Wolves Windows 7 Home Premium 64bit 9,642 posts California Quote: Originally Posted by Dwarf Let's go through this step by step. a = sqr (b) / k + 2 sqr (b) / k = a - 2 sqr (b) = k (a -2) sqr (b) = ka - 2k b = (ka - 2k) x (ka - 2k) b = kČaČ - 4kČa + 4kČ (answer) Check using a = 6 and k = 3 b = (3Č x 6Č) - (4 x 3Č x 6) + (4 x 3Č) b = 324 - 216 + 36 b = 144 Substituting b = 144 into the first equation, a = sqr (b) / k + 2, we get a = (sqr (144) / 3) + 2 a = (12 / 3) + 2 a = 4 + 2 a = 6 So the answer is b = kČaČ - 4kČa + 4kČ Not bad, considering that it is about 30yrs since I did any Algebra. Hopefully, this should help you with the rest of the questions if you approach them in a similar way. Don't forget to do the checking, substituting actual numbers, as shown above. You will need to work out for yourself suitable numbers to use at this step. Dwarf, Nice job going step by step in solving his problem. Could have done that early on in the post but thought it was important for the OP to practice and learn on his own. Isn't that the way we learned how to algebra? My System Specs
 05 Oct 2010 #40 Dwarf Windows 8.1 Pro RTM x64 10,375 posts Doncaster, UK I'm leaving the rest for him to work out on his own. Besides, the image isn't very clear with the other equations. My System Specs