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What would be affordable 32gb memory capacity desktop models?
Also if you have 32gb in your computer but use only 8gb in day to day activities does it still cost more electricity because all 32gb are running?
Also if you have 32gb in your computer but use only 8gb in day to day activities does it still cost more electricity because all 32gb are running?
First off it very hard to use up 8 gigs of ram unless you do things like CAD, video editing ect. Having extra ram that isn't being use doesn't use any more electricity that can be measured in any ordinary fashion. (Electric bill) Their is probable someone in a lab environment that has measured it to the power of 10. I have 12 gigs of ram and seldom use more than 3 gigs. 32 gigs of ram is a extreme amount.
Their are some that need that amount with what they use their computer for.
If you completely fill in your spec and tell us what you use your computer for we could give better advice.
Unless you're possibly gaming or running SAP or some business program.. 8GB is probably enough.
As an example, I opened Photoshop 64Bit, XP Mode- compiled a small program on Visual Studio 6.0 and opened up MSDN 6.0 together. They used a total of 2.8G of RAM.
What kind of apps are you planning on running? It would help to know- so we can advise you better.
[QUOTE=Lady Fitzgerald;2413348][QUOTE=dperecky;2413342]If you look at a power cable for a laptop, there is a little box on the cord. That box is essentially the power supply for the laptop. You will read on it a rated voltage and amperage that it delivers. That rated voltage and amperage are values that don't change too easily... You might get more coming out of it if you load up the laptop with a lot of USB type devices that need voltage... but then you're running your pc with an extraordinary draw on your power supply, which will make it run hotter than usual.... not good. If you keep it up, you will have to replace your power supply... as it cannot continue to deliver outside what it's rated and manufactured to deliver. The same principle goes for built-in power supplies in a desktop.
Really they're not that smart. Some company should make some that are smarter. That would be a nice change.
Unlike a conventional transformer that you find in many adapters for the likes of battery chargers and those that allow you to run devices from an external mains supply rather than their built-in batteries (and which will consume the same amount of power regardless of load), modern PSUs found in computers are rather more intelligent. They will just draw enough power from the mains (plus a small overhead for the PSU itself) in order to supply the current load placed on it. This is dynamic, and will vary depending on what the computer is doing (e.g. there will be a slight increase in power consumption when the optical drive is working compared to when it is idle).
[QUOTE=dperecky;2413371][QUOTE=Lady Fitzgerald;2413348]Baloney Sausage! That proves nothing. The rating on a laptop power adapter is the maximum it is rated for (same for a desktop PSU). The idle current draw is going to be much less than when the laptop is charging the battery and is running. The PSU on both laptops and desktops will deliver only as much as is needed by the computer and any attached peripherals. The actual PSU current draw will be proportional to the demand.
Not quite true. While battery chargers, etc. do have a standby current draw, they also do not run at the same amount no matter the draw. The amount of current they draw will increase as the amount of load on them is increased (such as adding batteries). They are very inefficient when the load is low and the efficiency improves as load is added (up to a point, generally near their rated capacity). Battery eliminators will consume less power when idle (disconnected from the device they power). If a partial load is put on them (such as a device put on an eliminator that is rated for twice as much as the device draw), the eliminator will not run at full capacity.
The output voltage of a power supply is determined by it's design. The output current is determined entirely by the load. This does not require any intelligence in the power supply, just basic ohms law. The formula is I=V/R.
I=current
V=voltage
R=resistance (the load)
With no load the current drain will be zero. Due to some small overhead the the input current to the power supply will be non-zero but quite small. Modern supplies are quite good at keeping this low. The current rating is just that, a maximum rating.
I did electronics service for a living for some 30 years so I know something (actually quite a lot) about these things.