Multiple Win7 showing in boot manager

battlese · 31 Mar 2011

I'm setting up new pc's for my office. I've created a reference pc and created a wim file. I next deploy the image to another (identical) pc by doing this:

booting to winpe disk
typing diskpart
selcting the volume
typing "clean"
creating a primary partition
format quick fs=ntfs
active
assign letter=c
then going to the cd drive and typing imagex/apply d:\win7img.wim 1 c:\
after it dumps the image on the drive I type bcdboot c:\windows /l en-us
wpetuil reboot

after it boots it shows the windows boot manager and under the "choose an operating system" it has Windows 7 listed twice. I can choose one and once into windows I go into msconfig boot tab. It shows the first Windows 7 at c:\windows and then second Windows 7 at \windows (no c:\). Weird!

Is there any way I can avoid having to go in and delete the second listing? I'm setting up roughly 650 pc's and will go crazy if I have to do it to each one.

Any help is appreciated!

SIW2 · 31 Mar 2011

Delete the bcd entry from the wim image.

Simplest way is to mount the image,you can use this: DISMGUIx86x64.zip

Then borrow this : BcdTool.zip

click Open - browse to the boot folder in the mounted image [Click Boot Config>Open ], pick up BCD - highlight the \windows entry, and select Remove Entry [Click Edit >Remove Selected Entry].

[ The boot folder you are looking for is the hidden system folder - pale yellow - I am sure you know that - just for the benefit of anyone else who sees the thread ]

Then unmount with commit.

After you apply the image,typing bcdboot command you are already doing will put the fresh entry in - the c:\windows one.