New
#1
Unsubscribing from office 365
This is doing my head in.
I was a nominated user of my GF's Office 365 (5 seat) account. It recently expired, she has no intention of renewing it.
I decided to redeem my free Office 365 Personal licence (free when I purchased my new Lumia).
I can't check out the product because the system sees that I am currently subscribed via her account. I follow the link to My Account. there is a hyper link that offers to unsubscribe me from her account.
https://i.imgur.com/eS5RnyP.jpg?1
When I click on it a blank box pops up. Nothing happens.
I have tried various browsers and even tried Edge on my phone. Still nothing.
I contacted MS support and the agent logged into my PC. He was unable to do anything more than I had. I was then put through to Billing and Subscriptions. The agent there told me that it is impossible to unsubscribe without the primary account holder unsubscribing you. I told him about the hyperlink.
He didn't seem to believe that it existed. Eventually he told me to use a different Wifi network and try the link again. Then he suggested setting up a brand new MS account (yeah like I want to lose my phone back ups and purchase history).
I tried to contact billing again. The new agent told me that I don't have a subscription.... When I insisted that I am subscribed, she deferred to a colleague, I can only assume that it was the earlier fellow. Again I was told that it is impossible to unsubscribe without the other person booting you off their subscription.
I find it very hard to believe that you cannot unsubscribe on your own, and if you can't why is there a hyper link in the first place? Looking at the HTML source code, I can see that there are supposed to be various messages in the box, one of which confirms the unsubscription.
What happens if the primary account holder dies or disappears?
I have been trying to sort this out for the last 4.5 hours.
And yes, I can ask my GF to sort it out for me but that wont happen today, assuming that she can even remember her log in details.