newer CPU on previous generation chipset = automatic performance loss?

[7point5]

to elaborate: since a given socket can cover 2 generations of chipsets/mainboards (for instance LGA1155 CPUs like Sandy & Ivy are handled by both P67 boards (with bios update) and H77/Z77 boards, and LGA1150 CPUs like Haswell & Broadwell are handled by both z87 boards (with bios update) and h97/z97 boards), question is:

if a newer cpu is put on an board with previous generation chipset (after having updated bios) will there be a performance loss/bottleneck caused by the older board?

for instance if I put a broadwell cpu on a haswell board (by that I mean a z87 chipset board) or an ivy cpu on a sandy board (eg. p67 chipset) can the cpu still be used to its full power or will there be a performance loss compared to the same cpu on the next generation chipset board? (the generation that was developed at the same period as the cpu: z77 for ivys, z97 for broadwells)

PS. and by performance I mean only the ones users care about: framerate in 3D games, raw computing power like compression & divx encoding, u get the picture

PPS. and to make the question worthwhile let's assume the most powerful CPU is being used for that socket (eg. an intel i7 3xxx or i7 5xxx with 4 real cores & 8 virtual cores with HT enabled in bios)



again I researched this extensively & can conclude that no one on the internet seems to know this +_-

 

[Megahertz07]

Never did but if the MoBo has the latest update, you can use it for same socket (1155, 1150 or 1151).
Only exception I know is Coffee lake CPU that has to run on 3xx chipset.

 

[7point5]

what about performance hit is there any performance hit?

 

[Megahertz07]

No reason for performance degradation. But new chipsets can have peripherals improvements (SATA, USB etc).

 

[7point5]

But new chipsets can have peripherals improvements (SATA, USB etc).

so that's the only difference with older chipsets?

both can handle new cpus equally? (the be difference in cpu benchmarks between older & newer boards?)