Your age by eating out

[echrada]

YOUR AGE BY EATING OUT

Don't tell me your age; you probably would tell a falsehood anyway-but your waiter may know!


YOUR AGE BY DINER & RESTAURANT MATH

This is pretty neat

DON'T CHEAT BY SCROLLING DOWN FIRST !

It takes less than a minute. Work this out as you read .

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat. (more than once but less than 10)

2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50

5. If you have already had your birthday this
year add 1758...

If you haven't, add 1757.

6. Now subtract the four digit year that you were born.

You should have a three digit number
The first digit of this was your original number. ( I. e., How many times you want to go out to restaurants in a week.)

The next two numbers are
YOUR AGE! ------ (Oh, YES!, it is!)

 

[smarteyeball]

Well I'll be damned. It was right

 

[Joe]

Very clever!

 

[NormCameron]

YOUR AGE BY EATING OUT

Don't tell me your age; you probably would tell a falsehood anyway-but your waiter may know!


YOUR AGE BY DINER & RESTAURANT MATH

This is pretty neat

DON'T CHEAT BY SCROLLING DOWN FIRST !

It takes less than a minute. Work this out as you read .

Be sure you don't read the bottom until you've worked it out!

This is not one of those waste of time things, it's fun.

1. First of all, pick the number of times a week that you would like to go out to eat. (more than once but less than 10)

2. Multiply this number by 2 (just to be bold)
3. Add 5
4. Multiply it by 50

5. If you have already had your birthday this
year add 1758...

If you haven't, add 1757.

6. Now subtract the four digit year that you were born.

You should have a three digit number
The first digit of this was your original number. ( I. e., How many times you want to go out to restaurants in a week.)

The next two numbers are
YOUR AGE! ------ (Oh, YES!, it is!)

Okay. Thats goood

Norm

 

[darkassain]

too good
are you breaking the fabric of space and time???...lol

 

[limneos]

Really good one...well done!

 

[johngalt]

It's a mathematical trick. The first part allows the orignal number to be multiplied by 100 and added to 250. The second part (adding the 1758) brings it to a nice round number that, when manipulated correctly (i.e. subtracting your birth year) reveals your age plus the original number multiplied by 100.

think about it....

X

time 2 = 2x
+5 = 2x + 5
X50 = 100x + 250....

and so on.

Of course, as soon as next year starts, the numbers 1758/1757 have to be incremented by 1 for it to work....

 

[NormCameron]

It's a mathematical trick. The first part allows the orignal number to be multiplied by 100 and added to 250. The second part (adding the 1758) brings it to a nice round number that, when manipulated correctly (i.e. subtracting your birth year) reveals your age plus the original number multiplied by 100.

think about it....

X

time 2 = 2x
+5 = 2x + 5
X50 = 100x + 250....

and so on.

Of course, as soon as next year starts, the numbers 1758/1757 have to be incremented by 1 for it to work....

It's not is it?. And I thought he was a mentalist too. Shame echrada for leading us on!

​

 

[johngalt]

Sorry to burst yer bubble, but it is.

And if you make the change I specify then it works again next year

 

[Se7en kbs]

OK it's a trick but it's very cool!

 

[Sleep]

It's off by one .

 

[johngalt]

It's a mathematical trick. The first part allows the orignal number to be multiplied by 100 and added to 250. The second part (adding the 1758) brings it to a nice round number that, when manipulated correctly (i.e. subtracting your birth year) reveals your age plus the original number multiplied by 100.

think about it....

X

time 2 = 2x
+5 = 2x + 5
X50 = 100x + 250....

and so on.

Of course, as soon as next year starts, the numbers 1758/1757 have to be incremented by 1 for it to work....

Cause it is 2009 - hence you need to adjust it (1758) by one also.